Editing Batch Mode and Command-Line Arguments

Basic code to check for presence of command line arguments and NOT open up a window:

        If My.Application.CommandLineArgs.Count > 0 Then
            CommandLineMain()
            Me.Close()
            Exit Sub
        End If

Then, CommandLineMain is similar to:

    Public Sub CommandLineMain()
        SetUpLogFile()
        MakeInitialLogEntries()
        'MsgBox("In CommandLineMain")

        Try
            ProcessShellRequest(System.Environment.GetCommandLineArgs, "Command Line")
            If System.Environment.ExitCode = 0 Then
                System.Environment.ExitCode = 1
            End If
        Catch ex As Exception
            System.Environment.ExitCode = -1999
            LogFile.LogEntry("** Shell Request exited with error code -1999; error message follows:")
            LogFile.LogEntry(ex.Message)
        End Try

        MakeFinalLogEntries()
    End Sub

See [[ProcessShellRequest]] for one way to process the single command on the command line.