http://rayharwood.com/Wiki/index.php?action=history&feed=atom&title=Batch_Mode_and_Command-Line_ArgumentsBatch Mode and Command-Line Arguments - Revision history2026-11-06T06:24:18ZRevision history for this page on the wikiMediaWiki 1.20.3http://rayharwood.com/Wiki/index.php?title=Batch_Mode_and_Command-Line_Arguments&diff=27&oldid=prevRayharwood: Initial creation2013-04-26T13:54:14Z<p>Initial creation</p>
<p><b>New page</b></p><div>Basic code to check for presence of command line arguments and NOT open up a window:<br />
<br />
If My.Application.CommandLineArgs.Count > 0 Then<br />
CommandLineMain()<br />
Me.Close()<br />
Exit Sub<br />
End If<br />
<br />
Then, CommandLineMain is similar to:<br />
<br />
Public Sub CommandLineMain()<br />
SetUpLogFile()<br />
MakeInitialLogEntries()<br />
'MsgBox("In CommandLineMain")<br />
<br />
Try<br />
ProcessShellRequest(System.Environment.GetCommandLineArgs, "Command Line")<br />
If System.Environment.ExitCode = 0 Then<br />
System.Environment.ExitCode = 1<br />
End If<br />
Catch ex As Exception<br />
System.Environment.ExitCode = -1999<br />
LogFile.LogEntry("** Shell Request exited with error code -1999; error message follows:")<br />
LogFile.LogEntry(ex.Message)<br />
End Try<br />
<br />
MakeFinalLogEntries()<br />
End Sub<br />
<br />
See [[ProcessShellRequest]] for one way to process the single command on the command line.</div>Rayharwood